Aquarterback back pedals 2.2 meters southward and then runs 6.8 meters northward, what is the distance, the magnitude, and direction?

The total distance covered by the cyclist is 9 m, while the displacement is 4.6 m northwards.

The given parameters;

Distance is scalar quantity. That is, distance can be represented in a complete sense with magnitude only.

The total distance covered during the motion = 2.2 m + 6.8 m = 9m

The direction describes the position of the total displacement.

The displacement = (6.8 m - 2.2 m) northward

The displacement = 4.6 m northward.

Thus, we can conclude that the total distance covered by the cyclist is 9 m, while the displacement is 4.6 m northwards.

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Distance moved = 9.0 m

Displacement magnitude = 4.6 m

Direction : Northwards

Explanation:

the quarter back pedals 2.2 m South

Then he pedal 6.8 m North

So here we can say that total distance moved by the quarterback is

Now to find the displacement we need to add them with direction

so we have

Direction : Towards North

e/c, where e is its total energy