Afeather is dropped on the moon from a height of 1.40 meters. the acceleration of gravity on the moon is -1.67 m/s^2. determine the time for the feather to fall to the surface of the moon?

We can use a simple equation to find the time for the feather to fall to the surface. y = (1/2) g t^2 y is the height g is the acceleration due to gravity t is the time t^2 = 2y / g t = sqrt{ 2y / g } t = sqrt{ (2) (1.40 m) / (1.67 m/s^2) } t = sqrt { 1.6766 s^2 } t = 1.29 seconds It takes 1.29 seconds for the feather to fall to the surface.

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