Acollision cart runs off the edge of a lab table that is .95 meters high. how fast did the collision cart leave the tabletop if the cart lands .40 meters from the base of the table?

From the given values we can generate the equations:

x = vx*t 
y = 0.95 - 1/2*g*t^2 

where x refers to displacement in horizontal direction, y refers to displacement in vertical direction, and t is time, while vx is velocity of the cart in the x direction, and g is the acceleration due to gravity = 9.8 m/s^2

At it's landing point we have x = 0.4, y = 0: 

0.4 = vx*t 
0 = 0.95 - 1/2*9.8*t^2 

Therefore combining the equations and solving:
t = 0.44 s s 
vx = 0.91 m/s

the cellphone, they would then know if the killer would have contacted them or always hated them. or if it was a breakup. but if that is not the case, then it would be the clothing. to put in a bullet, it would have to be put in by hands. hands have finger prints which, would have giving you the answer of who done it.

explanation: