How much heat is absorbed by a 29g iron skillet when its temperature rises from 9oc to 105oc?

We have:

Mass (m) of the iron skillet = 29 grams
Difference in temperature (Δt) = 105 - 9 = 96°C
Heat capacity of iron = 0.449 J/g °C

The energy (Q) is given by:

Q = m × Δt × specific heat
Q = 29 grams × 96 °C × 0.449 J/g°C
Q = 1250.016 Joules

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