You and a friend stand on a snow-covered roof. you both throw snowballs from an elevation of 15 m with the same initial speed of 13 m/s, but in different directions. you throw your snowball downward, at 40° below the horizontal; your friend throws her snowball upward, at 40° above the horizontal. what is the speed of each ball when it is 5.0 m above the ground? (neglect air resistance.)

Refer to the diagram shown below.

g = 9.8 m/s², and air resistance is ignored.

Let us consider the two trajectories.

Case A; The ball is launched 40°  below the horizontal
u = (13 m/s)*cos 40° = 9.9586 m/s, the horizontal velocity
v = -(13 m/s)*sin 40° = -8.3562 m/s

When the ball is at 5 m above ground, it would have traveled 10 m. 
The vertical downward velocity is
V² = (-8.3562 m/s²)² + 2*(-9.8 m/s²)*(-10 m) = 265.826
V = +/-16.304 m/s => V = -16.304 m/s  (downward)
The horizontal velocity remains unchanged.
The speed of the ball is
√[(-16.304)² + 9.9586²] = 19.105 m/s

Case B: The ball is launched 40° above the horizontal.
u = 9.9586 m/s, as in case A
v = 8.3562 m/s

When the ball is 5 m above ground, the vertical velocity, V, is given by
V² = (8.3562 m/s)² + 2*(-9.8 m/s²)*(-10 m) = 265.826
V = +/- 16.304 m/s
The speed of the ball is 
√[(-16.304)² + 9.9586²] = 19.105 m/s

Surprisingly, both speeds are the same.

The speed of the ball when it is 5 m above ground is 19.1 m/s (both cases).

Try b? sorry if i’m incorrect