Three dogs are pulling on a peg. Two are pulling in the same direction with forces of 85 N and 65 N, respectively. The third dog is pulling in the opposite direction with a
force of 70 N. What force does the peg need to resist to keep from being pulled out?
Show your reasoning.

Ithink the answer is fusion 

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.