A 96 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 370 N . For the first 12 m the floor is frictionless, and for the next 12 mthe coefficient of friction is 0.23.Part AWhat is the final speed of the crate?

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Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

The answer is a.  i hope this