Object 1 has a mass of 3m and is moving to the right at a velocity of 4v. Object 2 has a mass of m is moving to the left at v. After the objects collide inelastically, object A is moving to the left at a velocity of v (one third of its original velocity). Derive an expression for the final velocity V of object B.

I am confused because I thought the when it is an inelastic equation, then that means that the objects stick together. So how can you find the final velocity of object B (also it shows that after the collision, the two objects to in fact split apart)?

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

the answer is neither ball has a charge.

because if they were both positively charged, they will repel each other.

if they were positively and negatively charged, they will seek.