14. A 0.140 kg baseball is thrown with a velocity of 28.0 m1/S It is struck with an average fore of $000.0 N. which results in a velocity of 37.0 m/S in the opposite direction. How long were the bat and ball in contact?
O 437 x10-3
O 130 x 10-25
O 1.82 x10-3
O 3.12 x10-25

the maxium height is 34m/s

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j