a train travels at 100km/h heading east to reach a twin in 4 hours. the train then reverses and heads west at 50km/h for 4 hours what is the train’s position now

Solution: The first change in position is (+100 km/h) × (4 h) = +400 km. The second change in position is (-50 km/h) × (4 h) = –200 km.

The final position is (+400 km) + (-200 km) = +200 km. The train is 200 km east of where it started.

Explanation:

the ima (higher than 1m) will be greater than the ima with the height of 1m.