An engineer is designing a runway. She knows that a plane, starting at rest, needs to reach a speed of 180mph at take-off. If the plane can reach this take-off speed in 65.0s, how far will the plane travel before take-off. Assume the plane increases speed steadily. How far does the plane need to travel during take-off (in given units)?
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Could the plane take off on a 10000ft long runway?

The plane would need to travel at least (.)

The runway should be sufficient.

Explanation:

Convert unit of the the take-off velocity of this plane to :

.

Initial velocity of the plane: .

Take-off velocity of the plane .

Let denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation .

Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration times average velocity .

The distance that the plane need to cover would be:

.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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answer; equivalent to a one(1) horsepower motor;