A ball is dropped from a height of 50m. What will be its velocity before touching ground?

Statement:

A ball is dropped from a height of 50 m.

To find out:

The velocity of the ball before touching the ground.

Solution:

Initial velocity (u) = 0 m/s [since the ball was at rest before it was dropped]Height (h) = 50 mAcceleration due to gravity (g) = 9.8 m/s²Let the velocity of the ball before touching the ground be v.We know, the equation of motion for a freely falling body, v² = u² + 2gh.Putting the values in the above equation, we getv² = [(0)² + 2(9.8)(50)] m/sor, v² = 980 m²/s² or, v = √980 m/sor, v = 31.3 m/s

Answer:

The velocity of the ball before touching the ground is 31.3 m/s.

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Centrapedial force is the answer