The resistivity of copper is 1.77×10-11 Ωm. A copper wire of length 56.5 cm and cross-sectional area 1×10-6m2 is connected to the two sides of a 9 V battery. If no other resistance is connected to the battery, what will be the current flowing in the wire? 9.0×105 A

1.0×105 A

2.9×105 A

1.1×105 A

Current I is 9 × 10^-5

Explanation:

Data :

resistivity = p = 1.77 × 10^-11 ohm m

Lenght = L = 56.5 cm = 0.565 m

Area = A = 1 ×10^-6 m²

Potential difference = V = 9v

Formula for resistivity

 p = (RA)/ L

Put values

R = (p L)/A

R = 1 × 10^-5

Formula to find current I

V = IR   or I = V/R

Put values

I = 9 /1 × 10^-5

    I = 9 × 10 ^-5 A

im not to sure what it is

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.