An object accelerates from rest (v0), with a constant acceleration of 8.6 m/s^2 (a), what will its velocity (v) be after 7.2 s (t)? (Hint: use Kinematics Equation 1)

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

answerscientific theory;

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000