A ball is dropped off the side of a bridge. After 1.55 s, how far has it fallen?
(Unit = m)
Remember: Falling = -V
Lost height = -Ay
a = -9.80 m/s2 Be careful with minus signs!!!

second equation of motion

s = ut + 1/2at^2

s is the distance travelled time t

u is the initial velocity

t is the time

a is the acceleration of the body in motion

u is 0

s = 1/2 * -9.8 * (1.55)^2

s = -11.77 m

more than, less

less than, more

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .