The force F exerted on a ball during a collision with a wall is given as a function of time t by the equation F(t) = αt - βt2, where α = 400 N/s and β = 4000 N/s2. The ball first contacts the wall at t = 0, and the collision lasts for 0.10 s. What is the magnitude of the change in momentum of the ball? Group of answer choices

3.33 kg m/s, .67 kg*m/s, 0, 3.6

im sorry i dont know

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

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