A 4.0 kg mass stone is thrown vertically upwards at a speed of 20 m/s. I) determine the maximum height it reaches.
II) Determine your speed when in the
half of its maximum height.
III) Determine the total mechanical energy at this point. of
work performed by the gravitational force from the launch point to the return to that point.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

The correct answer is  ait's a process by which rocks and minerals undergo in their composition^o^

Idk idk idk idk idk idk idk idk idk ikd idkk