What would its deceleration be if the road is inclined at 9. 3 ∘ and the car moves uphill? assume the same static friction coefficient.

i would think form in reponse to tensional forces

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.

there are no contact forces mentioned on the list of choices that you've provided.