A 1 kg object is attached to a horizontal spring. It is stretched by 0.1 m and released from rest. It moves without friction. The next time the speed is zero is 0.5 s later. What is the maximum speed of the object

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j