A crate of mass 50kg is pulled up a rough inclined plane, inclined at an angle of 60° to the horizontal. Determine the total work done in moving the crate to the top of the inclined 200m high.

Wc = m*g = 50kg * 9.8N/kg = 490 N = Wt.

of crate.

Fc = 490N  60o = Force of crate.

Fp = 490*sin60 = 424.4 N. = Force

parallel to incline.

Fv = 490*cos60 = 245 N. = Force perpendicular to the incline.

Ff = u*Fv = u*245 = Force of friction.

Fap-Fp-Ff = m*a

Fap-424.4-u*245 = m*0 = 0

Fap = 424.4 + 245u. = Force applied.

L = 200m/sin60 = 231 m. = Length of

incline.

Work = Fap * L=(424.4+245u) * 231.

Explanation:

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: