A ball of mass 2.0 kg is travelling at a speed of 12 m/s. It moves towards an object of mass 3.0 kg which is at rest. The ball hits the object and sticks to it.

Which row gives the total momentum, and the speed of both objects immediately after the collision?

total momentum (kg m/s)
A- 0
B- 0
С- 24
D- 24

AND..

speed (m/s)
A- 4.8
B- 8.0
C- 4.8
D- 8.0

Centrapedial force is the answer

Ireally just need to get finished with precal! i’m really sorry i have to do this! hope this !

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j