a uniform metre rule of mass 100g balances at the 40cm mark when a mass X is placed at the 10cm mark what is the value of x. pls help I don't know how to solve it

The fulcrum of the metre stick is at the 40 cm mark

100 g * 10 cm = 1000 g-cm clockwise torque

x * 30 cm = 1000 gm-cm = counterclockwise torque for balance

X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm  at 10 cm to balance

answer: i think he can see forward ten seconds and move forward ten seconds but giorno can undo his actions with ger.

explanation: