A 15 kg chunk of ice falls off the top of an iceberg. If the chunk of ice falls 8m to the surface of the water what is its velocity?

When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE =  M g H

we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE

1/2 MV^2 = M g H

1/2 V^2 = g H

when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).

∴ v^2 = 2 * 9.8 * 8 = 156.8

∴ v= √156.8 = 12.5 m/s

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

0.55x745.7j and a calculator