A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rider together is 85 kg, what is the net force acting on the bicycle? (Hint: first, calculate acceleration) Acceleration = Fnet =

42.5km/s^2

Explanation:

Fnet=m⋅a

We know that

Here,  

v=4m/s,  u=0m/s,  t=8s

Also, we have  m=85kg

Fnet=85  kg⋅0.5  m/s2=42.5N

Acceleration = (change in speed) / (time for the change)

Acceleration = (4 m/s) / (8 seconds)

Acceleration = 0.5 m/s²

Force = (mass) x (acceleration)

Force = (85 kg) x (0.5 m/s²)

Force = 42.5 Newtons

Explanation:

We would need to use Newton's second law ofmotion, which states that-

We know that,

Here,v = 4 m/s, u = 0 m/s, t = 8 s

Also, we have

m = 85 kg