car accelerates uniformly from 5m/s to 15m/s taking 7.5 seconds. How far did it travel during this period?

Given :-

Initial Velocity (u) = 5 m/s

Final Velocity (v) = 15 m/s

Time (t) = 7.5 seconds

To Find :-

Distance (s) = ?

Solution :-

First of all we will find the acceleration of car :

→ Acceleration = Final Velocity - Initial Velocity ÷ Time

→ Acceleration = 15 - 5 ÷ 7.5

→ Acceleration = 10 ÷ 7.5

→ Acceleration = 1.3 m/s²

Now, by using Second equation of motion we can find distance travelled by the car :

→ s = ut + ½ at²

→ s = 5 × 7.5 + ½ × 1.3 × (7.5)²

→ s = 37.5 + ½ × 1.3 × 56.25

→ s = 37.5 + 1.3 × 28.125

→ s = 37.5 + 29.425

→ s = 66.925 m

Therefore,the distance travelled by the car is 66.925 m.

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation:

they should be similar or the same