Three forces act on the body: 0.4 N to the right side and up at the angle of 30° to the horizon, 0.7 N to the right side and up at the angle of 45°, and 0.8 N to the right side and up at the angle of 60° to the horizon. Find the projection of the resultant of these forces onto the vertical axis.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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