An object's angular acceleration is 36 rad/s^2. If it were initially spinning with a velocity of 6.0 m/s, what would its angular velocity be after 5.0 s?
a. 186 rad/s
b. 190 rad/s^2
c.-174 rad/s
d. -174 rad/s

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Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then