Question 1 Read the scenario carefully
Scenario 1: A runner is racing in a 10-kilometer (km) race. The runner travels the first 2
km in 12 minutes (min). Then the runner stops for 2 min to have a drink of water. He
begins running again, and covers the next kilometer in 5 min. The following 3 km have
the same pace: 6 minutes per kilometer (min/km). The runner again pauses to tie his shoe;
he is paused for 1.5 min. He has 4 remaining km to go. When he starts running again, he
runs 1 km in 5 min, but the remaining 3 km are each 1 min slower than the one before (6
min, 7 min, and 8 min, respectively). Create a distance-time graph to show the runner's
speed
Construct a distance-time graph to show how the object(s) in your scenario move(s) over
time. Remember that the y-axis represents the distance traveled by an object, and the x-
axis represents time. Include the appropriate units on your graph.

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

amplitude

hope this