You submerge 100 grams of steel in 200 grams of water. If the steel has an initial temperature of 90°C and the water has an initial temperature of 15°C, what is the final temperature of the system? The specific heat capacity of the steel is 0.15 cal/g•°C.

Q=cmΔT

Q1(steel)=Q2(water)

c1•m1• (t1-t) = c2•m2• (t-t2)

628•0.1•(80-t) = 4180•0.2• (t-10)

5024-62.8t = 836t -8360

5024+8360=(836+62.8)t

t=14.9°C

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

dang that balls went far