Pls answer i need answertt ill give brainliest

All in 3 significant figures

Q1: 38.8 m/s

Q2: 40.8 m/s

Q3: 80 m

Q4: 1.23 m/s^2

Q5: 12.2 m/s

Explanation:

Use the equation = + 2as where

v = final velocity

u = initial velocity

a = acceleration

s = distance travelled

Q1: Find final speed (v):

v^2 = 0^2 + (2 x 2.5 x 300)

v^2 = 1500

v = 38.8 m/s

Q2: Find final speed (v)

*Make sure to convert 1km into standard units (m)

*1km = 1000m

v^2 = 8^2 + (2 x 0.8 x 1000)

V^2 = 40.8 m/s

Q3: Find distance travelled (s)

First rearrange the equation to find s:

v^2 = u^2 + 2as

s = (v^2 - u^2) / 2a

Then solve with given values

s = (7^2 - 3^2) / (2 x 0.25)

s = 80 m

Q4: Find acceleration (a)

*Blurry picture so values may be off

*Make sure to convert km to standard units (m)

*2km = 2000m

First rearrange the equation to find a:

v^2 = u^2 + 2as

a = (v^2 - u^2) / 2s

Then solve with given values

a = (70^2 - 0^2) / (2 x 2000)

a = 1.23 m/s^2

Q5: Find final speed (v)

v^2 = 0^2 + (2 x 0.75 x 100)

v^2 = 150

v = 12.2 m/s

Note: When converting v^2 to v you must square both sides ()