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Physics, 20.09.2021 08:40 desiree6005

Một chất điểm chuyển động thẳng nhanh dần đều từ điểm A với vận tốc ban đầu 2m/s ,với gia tốc 4m/s^2 để tới B cách A 220(m).Chọn trục tọa độ trùng với đường thẳng AB, chiều dương hướng hướng từ A sang B ,gốc tọa độ tại A và chọn gốc thời gian lúc vật đi từ A 1.viết phương trình chuyển động của vật 2. Khi vật tăng tốc 2m/s lên 4m/s .Hãy tính thời gian, quãng đường vật đi được 3. Sau bao lâu thì vật tới B

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Một chất điểm chuyển động thẳng nhanh dần đều từ điểm A với vận tốc ban đầu 2m/s ,với gia tốc 4m/s^2...
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