The cannons in the diagram below are being fired horizontally off platforms of the different heights (as indicated). While each cannon shoots an identical cannonball, they do so with different velocities. Given the height of the platform and each cannon's launchelocity, what is the correct ranking, from greatest to least, for the range achieved by each cannonball? ​

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.