A. If two objects are thrown vertically downward, from the same height, with speeds v and with the object of y, thrown at time! thrown at time t = 0, and the other at a later time t = t after the first, derive an expression for the length of time T after which they collide​

massxgravity x heght=weightxheight= pe

4900=490xh

h=10

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.