During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where it hits the bat does it rise? Assume when it hits the ground it hits at exactly the level of the bat. The acceleration of gravity is 9.8 m/s 2 . Answer in units of

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

Now by substituting values in, we get

d = 19.796m

talk back to him about the sport and show him your expertise or leave the room

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach