Physics, 16.09.2021 07:50 keylor97

You throw a ball toward a wall with a speed of 25.0 m/s and at an angle of 40.0° above the horizontal. The wall is 22.0 m horizontally from the release point of the ball.
A. How far above the release point does the ball hit the wall?
B. What are the horizontal and vertical components of the velocity as the ball hits the wall?

PLEASE HELP

Answers: 2

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Answer from: jaueuxsn

We adopt the positive direction choices used in the textbook so that equations such as Eq. 4-22 are directly applicable. The coordinate origin is at the release point (the initial position for the ball as it begins projectile motion in the sense of §4-5), and we let θ

be the angle of throw (shown in the figure). Since the horizontal component of the velocity of the ball is v

cos40.0°, the time it takes for the ball to hit the wall is

Δx

(25.0m/s)cos40.0

22.0m

=1.15s.

(a) The vertical distance is

Δy=(v

sinθ

)t−

=(25.0m/s)sin40.0

(1.15s)−

(9.80m/s

)(1.15s)

=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: v

cos40.0°=19.2m/s.

sinθ

−gt=(25.0m/s)sin40.0

−(9.80m/s

)(1.15s)=4.80m/s.

(d) Since v

>0 when the ball hits the wall, it has not reached the highest point yet.

Answer from: Quest

Ithink the answer would be 1,350!

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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