The efficiency of the first machine is 20.0 percent and the efficiency of the second machine is 80.0 percent. If 32,000 joules
of energy is supplied to the first machine, what is the work output
of the second machine?

Please help I need this by today

most probably 5120J. or 32000x0.8= 25600J

Explanation:

the 1st machine has 20% efficiency. if we supply 32000 joules to the 1st machine then the work output is 32000x0.2 = 6400 J.

if this output from the 1st machine with an output of 6400J is passed through the second machine with an efficiency of 80% then we get 6400x.80 = 5120J.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.