2 points The following graph represents the relationship between the weight someone can bench press and the time spent in training: (The values for the slope and the vertical-intercept have been provided for you underneath the graph -- you do not have to calculate them!) Predict the weight the person could bench press after 8 months of training, assuming the rate of improvement remains constant.* 200 d 160 120 Weight (lbs) 80.0 40.0 0.00 0.00 4.00 5.00 1.00 2.00 3.00 Time in training (months) Slope Y Intercept C. O.R. Statistics Data Set 1 20.020.00 110:0.00 1.00 0 20.0 lbs 0 270 lbs 160 lbs O 110 lbs​

Iwould choose the same momentum because if they throw a baseball very light and not hard at all then doing it with a bowling ball won’t hurt that worse

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    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s