A pair of charged conducting plates produces a uniform electric field of 9,000 N/C, directed from plate A toward plate B, between the plates. The separation of the plates is 50 mm. An electron is projected from plate A, directly toward plate B, with an initial speed of v0 = 1.6 × 10^7 m/s, as shown. What is the speed of the electron when it strikes plate B? (e = 1.60*10^-19; mass electron = 9.11*10^-31)

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

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initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft