The position-time equation for a cheetah chasing an antelope is: xf = 1.6m + (1.7m/s2)t2
(a) What is the initial position of the cheetah?
(b) What is the initial velocity of the cheetah?
(c) What is the cheetah's acceleration?
(d) What is the position of the cheetah at t = 4.4s?

1/0.14nm = 10^10/1.4 a lot

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j