A mass spring system is in SHM in the horizontal direction. if the mass is 0.25kg, spring constant is 12N/m, and the amplitude is 15cm, a) what is the maximum speed of the mass ? b) what is the speed at a half-amplitude position? ​

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96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.