69. Two cars travel along a straight road. When a stopwatch
reads t = 0.00 h, car A is at xa = 48.0 km moving at a
constant speed of 36.0 km/h. Later, when the watch
reads t = 0.50 h, car B is at Xp = 0.00 km moving at
48.0 km/h. Answer the following questions, first
graphically by creating a position-time graph and
then algebraically by writing equations for the posi-
tions xa and xp as a function of the stopwatch time (t).
a. What will the watch read when car B passes car A?
b. At what position will car B pass car A?
c. When the cars pass, how long will it have been
since car A was at the reference point?
Answers: 2
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Select all the correct answers. which changes will increase the rate of reaction during combustion? decreasing the area of contact between the reactants adding more oxygen to the reaction removing heat from the reaction changing the reactants from solid form to powdered form lowering the exposure of the reactants to air
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Two conductors, a and b, are each in the shape of a tetrahedron. but of different sizes. they are charged in the following manner: 1. tetrahedron a is charged from an electrostatic generator to charge q. 2. tetrahedron a is briefly touched to tetrahedron b. 3. steps 1 and 2 are repeated until the charge on tetrahedron b reaches a maximum value. if the charge on tetrahedron b was q/4 after the first time it touched tetrahedron a. what is the final charge qbmax on tetrahedron b?
Answers: 2
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Convection currents are caused by differences in what two things?
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Ablock of mass m slides on a horizontal frictionless table with an initial speed v0 . it then compresses a spring of force constant k and is brought to rest. the acceleration of gravity is 9.8 m/s2. how much is the spring compressed x from its natural length? 1) x = v0*sqrt(k/(mg)) 2) x=v0*sqrt(m/k) 3) x=v0*((mk)/g) 4) x=v0*sqrt(k/m) 5) x=v0*(m/kg) 6) x=v0*sqrt((mg)/k) 7) x=(v0)^2/(2g) 8) x=v0*(k/(mg)) 9) x=(v0)^2/(2m) 10) x=v0*((mg)/k)
Answers: 3
69. Two cars travel along a straight road. When a stopwatch
reads t = 0.00 h, car A is at xa = 48....
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