Standing at the edge of a cliff 32.5m high, you do a ball. Later, you throw a second ball downward with an initial speed of 11m/s. Calculate the velocity if each of the balls when it hits the ground

The displacement of the ball

ℎ =

2 −

2

2

So, final speed of the first ball

1 = √2ℎ = √2 × 9.8 × 32.5 = 25.24

m

s

The change of it speed

∆1 = 25.24 − 0 = 25.34

m

s

The final speed of the second ball

2 = √

2 + 2ℎ = 27.53

m

s

The change of the second ball speed

∆2 = 27.53 − 11 = 16.53

m

s

Thus

∆1 > ∆2

∆1 > ∆2

Explanation:

"i have always loved contemporary art and made it a general goal to work within the field. after a few nonprofit internships at museums and galleries, i decided to try the for-profit art world and was offered a job as the ad assistant at the magazine. i much prefer the pace of the for-profit art community and have stayed with the company for three years, with a promotion to an account manager last spring."

i just did this and got a 100.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever