Urkar is driving down the street at 11 m/s. What acceleration is required for him to slow to a stop in 2 s?

-5.5m/s^2

Explanation:

Well first of all, we know that velocity is a vector, therefore acceleration is a vector. And since urkar is slowing down, the acceleration will be negative

V1 = 11m/s

V2 = 0m/s ( bcuz they said to a stop)

t = 2s

a = V2 - v1

- - - - - - - - - -

t

a = 0 - 11

- - - - - - -

2

= - 5.5ms^-2

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .