Find the effort , if load is 500N , load distance is 0.5m and effort distance is 2.5m​

Explanation:

Solution:

Load(L)=500N

Load distance(Ld)=0.5m

Effort(E)=?

Effort distance(Ed)=2.5m

Now,

We know that,

E×Ed=L×Ld

or,E=L×Ld

Ed

or,E=500N×0.5m

2.5m

or,E=100N

Hope it help for you.Plz mark as brainliest as your wish.Have a nice day.

6 cos 34, 6 sin 34 trig

we need to know the time interval during which the force acts. impulse of force = momentum change