A charge feels a 7.89 x 10-7 N force when it moves 2090 m/s at a 29.4° angle to a 4.23 x 10-3 T magnetic field. What is the amount of the charge?

From the question, the given charge moving within the magnetic field would have a value of 1.82 x C.

A charge is either a positively or negatively charged particle. When a charge is moving through a magnetic field, it would experience a force which depends on the amount of the charge, its speed, the magnetic field strength and angle. The force on a charge in a magnetic field can be determined by:

F = qvBSin θ

where: q is the charge, v is its velocity/ speed in the field and θ is the angle of deflection of the charge.

Given that: F = 7.89 x N, v = 2090 m/s, B = 4.23 x T and θ = 29.4°.

Thus, the amount of the charge can be determined by;

q =

  =

  =

q = 1.818 x

q = 1.82 x C

Therefore, the amount of the charge that moved within the magnetic field is 1.82 x C.

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We have that the amount of the charge q is

From the Question we are told that

Force

Velocity

Angle

Magnetic field

Generally, the equation for Force F is mathematically given by

In conclusion

The amount of the charge q is

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