Which statement best describes the arrangement of electrons in an atom of fluorine (F)? (1 point) giving brainliest for sure

There are two electrons in the first energy level and seven electrons in the second energy level.

There are two electrons in the first energy level and five electrons in the second energy level.

There are five electrons in the first energy level and two electrons in the second energy level.

There are seven electrons in the first energy level and two electrons in the second energy level.

Flourine is an element which has 9 electrons. The first energy level can only hold upto 2 electrons so therefore two electrons of the fluorine element will be in the first orbital.

In the second orbital there will be seven electrons. The configuration will be as 1s2, 2s2 , 2p5 .

The first orbital has capacity of two electrons and then the remaining two electrons will be in higher second energy level.

The further 5 electrons will be in lower second energy level which is denoted by p.

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#1. 5

#2.They have valence electrons in the same energy level.

#3. Helium atoms have 2 valence electrons, while atoms of the other elements in the group all have 8 valence electrons.

#4. cesium (Cs)

#5.  There are two electrons in the first energy level and seven electrons in the second energy level.

Explanation:

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explanation:

the second one and the forth one are in the purple because they are opinions and the rest are in the yellow

explanation: