Suppose a 32-pound weight stretches a spring 2 feet. If the weight is released from rest at the equilibrium position, find the equation of motion x(t) if an impressed force f(t) = 12t acts on the system for 0 ≤ t < 5 and is then removed (see Example 5 in Section 7.3). Ignore any damping forces. (Use g = 32 ft/s2 for the acceleration due to gravity.)

Amagnetic field "does not" interact with stationary electric charges. so, a.hope my answer you : )

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.