A circular saw blade of diameter 0.210 m starts from rest. In a time interval of 6.40 s it accelerates with constant angular acceleration to an angular velocity of 132 rad/s with constant angular acceleration. Find the angular acceleration and the angle through which the blade has turned in this time. So, I used α=Δω/Δt = (140 rad/s)/(6.00s) = 23rad/s
Is this answer right?
Also, to find θ, which equation do I use??? Do I use Δθ=ω0t+1/2αt2 or can I simply use Δθ=ωΔt as derived from the equation ω=Δθ/Δt?