B. Block on an incline A block of mass mı = 3.9 kg on a smooth inclined plane of angle 38° is connected by a cord over a small frictionless
pulley to a second block of mass m2 = 2.6 kg hanging vertically. Take the positive direction up the incline and use 9.81
m/s2 for g.
What is the tension in the cord to the nearest whole number?

Block on the incline:

• net force parallel to the incline

∑ F (para.) = m₁ g sin(38°) - T = m₁ a

where T is the magnitude of tension in the cord.

Notice that we take down-the-incline to be the positive direction, so that if the 3.9-kg block pulls the 2.6-kg block upwards, then the acceleration of the system is positive.

Suspended block:

• net vertical force

∑ F (vert.) = T - m₂ g = m₂ a

Solve both equations for the acceleration a, set the results equal to one another, and solve for T :

a = g sin(38°) - T/m₁

a = T/m₂ - g

==>   g sin(38°) - T/m₁ = T/m₂ - g

==>   T (1/m₂ + 1/m₁) = g (sin(38°) + 1)

==>   T = g (sin(38°) + 1) / (1/m₂ + 1/m₁)

==>   T = (9.81 m/s²) (sin(38°) + 1) / (1/(2.6 kg) + 1/(3.9 kg)) ≈ 25 N

if i understood you you wish to calculate power from voltage and current.

we have voltage of 220 volts and current of 5.3 amperes. the power is equal to the product of voltage and current.

where p is power, u is voltage and i is current.

so,

hope this .

r3t40