Imagine hanging a 120 gm mass at the 10 cm mark of the meterstick (Masses stated in this experiment include the mass of the clip and hanger). Adjust the position of the fulcrum until the meter stick is balanced (at the 26 cm mark). The meterstick is in equilibrium because the torque due to the hanging weight is balanced by an opposite torque due to weight of the meter stick. a. Weight of the 100 gm mass plus clip and hanger = N (Force)
b. Wight of meter stick =

16. a brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800 n on him. the mass of the losing player plus equipment is 90.0 kg, and he is accelerating at 1.20m/s2 size 12{1 "." "20"" m/s" rsup { size 8{2} } } {} backward. (a) what is the force of friction between the losing player’s feet and the grass? (b) what force does the winning player exert on the ground to move forward if his mass plus equipment is 110 kg? (c) draw a sketch of the situation showing the system of interest used to solve each part. for this situation, draw a free-body diagram and write the net force equation.